Answers: (a) Flowchart: (b) Calculation of cyclomatic complexity Cyclomatic Complexity, M = E - N + 2P Where, E = no of edges N = no of nodes P = no of connected components Excluded the START and the END node; and corresponding edges N = 5 E = 6 P = 1 2P = 2*1= 2 Cyclomatic Complexity, M = 6 - 5 + 2Read more
Answers:
(a) Flowchart:
(b) Calculation of cyclomatic complexity
Cyclomatic Complexity, M = E – N + 2P
Where, E = no of edges N = no of nodes P = no of connected components
Excluded the START and the END node; and corresponding edges N = 5 E = 6 P = 1
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CODE: import java.io.*; import javax.servlet.*; import javax.servlet.http.*; import java.sql.*; public class Register extends HttpServlet { protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setContentType("text/htmlRead more
CODE:
Compute the derivatives df/dx of the following functions. Describe your …
Answer: A. B.
Answer:
A.
B.
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class Circle(): def __init__(cir, r): cir.radius = r def area(cir): return cir.radius**2*3.14 def perimeter(cir): return 2*cir.radius*3.14 NewCircle = Circle(8) print("Area : ",NewCircle.area()) print("Perimeter : ",NewCircle.perimeter())
(CYCLOMATIC/MCCABE COMPLEXITY) Consider the following bubblesort sorting algorithm: procedure bubbleSort( …
Answers: (a) Flowchart: (b) Calculation of cyclomatic complexity Cyclomatic Complexity, M = E - N + 2P Where, E = no of edges N = no of nodes P = no of connected components Excluded the START and the END node; and corresponding edges N = 5 E = 6 P = 1 2P = 2*1= 2 Cyclomatic Complexity, M = 6 - 5 + 2Read more
Answers:
(a) Flowchart:
(b) Calculation of cyclomatic complexity
Cyclomatic Complexity, M = E – N + 2P
Where, E = no of edges N = no of nodes P = no of connected components
Excluded the START and the END node; and corresponding edges N = 5 E = 6 P = 1
2P = 2*1= 2
Cyclomatic Complexity, M = 6 – 5 + 2 = 3
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Correct Option is (d) Abstract Data Type
Correct Option is (d) Abstract Data Type
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Correct Option is (c.) Stack .
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