Capacity of disk pack = Total number of surfaces x Number of tracks per surface x Number of sectors per track x Number of bytes per sector = 16 x 128 x 256 x 512 bytes = 2^28 bytes = 256 MB
Capacity of disk pack
= Total number of surfaces x Number of tracks per surface x Number of sectors per track x Number of
bytes per sector
= 16 x 128 x 256 x 512 bytes
= 2^28 bytes
= 256 MB
DECLARE get_ctr CHAR(1) := 'B'; BEGIN IF ( get_ctr >= 'A' AND get_ctr <= 'Z' ) OR ( get_ctr >= 'a' AND get_ctr <= 'z' ) THEN dbms_output.Put_line ('The given character is a letter'); ELSE dbms_output.Put_line ('The given character isRead more
DECLARE
get_ctr CHAR(1) := 'B';
BEGIN
IF ( get_ctr >= 'A'
AND get_ctr <= 'Z' )
OR ( get_ctr >= 'a'
AND get_ctr <= 'z' ) THEN
dbms_output.Put_line ('The given character is a letter');
ELSE
dbms_output.Put_line ('The given character is not a letter');
IF get_ctr BETWEEN '0' AND '9' THEN
dbms_output.Put_line ('The given character is a number');
ELSE
dbms_output.Put_line ('The given character is not a number');
END IF;
END IF;
END;
/
Consider a disk pack with following specifications 16 surfaces, 128 tracks per surface, 256 sectors per track & 512 bytes …
Capacity of disk pack = Total number of surfaces x Number of tracks per surface x Number of sectors per track x Number of bytes per sector = 16 x 128 x 256 x 512 bytes = 2^28 bytes = 256 MB
Solve the following quadratic programming problem(Wolf’s method) Maximize Z = 2×1+x2-x12, Subject to 2×1+3×2 ≤ 6, 2×1+x2 ≤ …
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See lessWrite a PL/SQL program to identify whether a character entered by user is letter or digit.
DECLARE get_ctr CHAR(1) := 'B'; BEGIN IF ( get_ctr >= 'A' AND get_ctr <= 'Z' ) OR ( get_ctr >= 'a' AND get_ctr <= 'z' ) THEN dbms_output.Put_line ('The given character is a letter'); ELSE dbms_output.Put_line ('The given character isRead more
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FOLLOW THE LINK: https://sikshapath.in/question/write-a-trigger-to-ensure-that-no-employee-of-age-less-than-25-can-be-inserted-in-the-database-2/
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