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    1. Asked: December 30, 2021In: DBMS

      There are three relations in the following schema for the company: 1. EMPLOYEE (National_ID, Employee_Name, Salary, Service_Unit), 2. EMPLOYER (National_ID, …

      I'M ADMIN
      I'M ADMIN
      Added an answer on December 30, 2021 at 9:08 pm

      1) insert into employee values('P129799311','Nohara Hiroshi',367000,'Kasukabe Defence Force'); 2) update employer set salary=65000 where employer_name='Isaac Netero'; 3) select * from employee where salary>75000 or salary between 30000 and 40000; 4) select avg(salary),count(national_id) from emplRead more

      1) insert into employee values(‘P129799311′,’Nohara Hiroshi’,367000,’Kasukabe Defence Force’);

      2) update employer set salary=65000 where employer_name=’Isaac Netero’;

      3) select * from employee where salary>75000 or salary between 30000 and 40000;

      4) select avg(salary),count(national_id) from employee;

      5) select employer_name,salary*0.05 from employer;

      6) select * from employee order by salary;

      CREATE TABLES BY YOUR OWN

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    2. Asked: December 30, 2021In: Programming Language

      Given reference, useful methods for accessing Java class ArrayList: add (elt): Add element to the end of the list, e.g. …

      I'M ADMIN
      I'M ADMIN
      Added an answer on December 30, 2021 at 8:57 pm

      package com.company; //BCity is a public subclass of City public class BCity extends City{ //bRList is a variable of type ArrayList and is initialied with an empty list List<String> bRlist = new ArrayList<>(); //The constructor has 3 arguments as mentioned BCity(String cN, int cP, StringRead more

      package com.company;
      
      //BCity is a public subclass of City
      public class BCity extends City{
          //bRList is a variable of type ArrayList and is initialied with an empty list
          List<String> bRlist = new ArrayList<>();
          //The constructor has 3 arguments as mentioned
          BCity(String cN, int cP, String[] rules){
              //super keyword calls the parent constructor with the input arguments
              super(cN, cP);
              this.bRlist = Arrays.asList(rules);
          }
          //hasRules has returnType of int and accepts an input parameter of type String
          public int hasRules(String rule){
              int flag = -1;
              //loop over brList
              for (int i = 0; i< this.bRlist.size(); i++) {
                  //whenever the element matches assign the value of flag and break the loop
                  if(this.bRlist.get(i) == rule){
                      flag = i;
                      break;
                  }
              }
              //return the value of flag
              return flag;
          }
          //dispRList has returnType of void and donot have any input parameters
          public void dispRList(){
              //this will display the city and population value
              System.out.println("City "+ this.cN + "Pop "+ this.cP);
              //loop over bRList to display as mentioned
              for(String rule: this.bRlist){
                  System.out.println(rule);
              }
          }
      }
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    3. Asked: December 30, 2021In: Mathematics

      If a boat is moving in upstream with velocity of 14 km/hr and goes downstream with a velocity of 40 …

      I'M ADMIN
      I'M ADMIN
      Added an answer on December 30, 2021 at 8:37 pm

      A. 13 km/hr   Explanation: Given: Upstream speed = 14 km/hr Downstream speed = 40 km/hr so, If speed of stream is y km/hr and speed of boat is x km/hr then Upstream speed = (x - y) km/hr and downstream speed = (x + y) km/hr Calculation: x + y = 40       ---- (i) and x - y = 14       ---- (ii) ∴Read more

      A. 13 km/hr

       

      Explanation:

      Given:

      Upstream speed = 14 km/hr

      Downstream speed = 40 km/hr

      so,

      If speed of stream is y km/hr and speed of boat is x km/hr

      then Upstream speed = (x – y) km/hr and downstream speed = (x + y) km/hr

      Calculation:

      x + y = 40       —- (i)

      and x – y = 14       —- (ii)

      ∴ x = 27 km/hr ——— { after solving eq (i) and eq(ii)}

      ∴ y = speed of stream = 40 – 27 = 13 km/hr

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    4. Asked: December 30, 2021In: Other

      _______________________ is the process of identifying an individual, usually based ona username and password. A. Authentication B. Authorization C. integrity D. crytography

      I'M ADMIN
      I'M ADMIN
      Added an answer on December 30, 2021 at 8:26 pm

      A. Authentication

      A. Authentication

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    5. Asked: December 30, 2021In: Other

      Firewalls are used to protect against A. Virus Attacks B. Fire Attacks C. Data Driven Attacks D. Unauthorized Attacks

      I'M ADMIN
      I'M ADMIN
      Added an answer on December 30, 2021 at 8:26 pm

      D. Unauthorized Attacks

      D. Unauthorized Attacks

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    6. Asked: December 30, 2021In: Other

      The secret key between members needs to be created as a ________key when two members contact KDC. A. public B. session C. complimentary …

      I'M ADMIN
      I'M ADMIN
      Added an answer on December 30, 2021 at 8:25 pm

      B. session

      B. session

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