Answer: serial data transmission reason: serial data transmission more reliable over long distances. less likely for the data to be skewed/out of synchronisation. less interference as only a single wire. a fast connection is not required as a printer is limited by its printing speed
Answer: serial data transmission
reason:
serial data transmission more reliable over long distances.
less likely for the data to be skewed/out of synchronisation.
less interference as only a single wire.
a fast connection is not required as a printer is limited by its printing speed
MEAN OF MONTHLY WAGES(A) = TOTAL WAGES / NO OF WORKERS TOTAL WAGES (A) = MEAN (A) * NO OF WORKERS(A) TOTAL WAGES (A) = 305 * 20 = 6100 IN THE SAME WAY, TOTAL WAGES (B) = 300* 25 =7500 TOTAL WAGES (C) = 340 * 40 =13600 Now add all these total wages(6100+7500+13600) and divide it by totaRead more
MEAN OF MONTHLY WAGES(A) = TOTAL WAGES / NO OF WORKERS
TOTAL WAGES (A) = MEAN (A) * NO OF WORKERS(A)
TOTAL WAGES (A) = 305 * 20 = 6100
IN THE SAME WAY,
TOTAL WAGES (B) = 300* 25 =7500
TOTAL WAGES (C) = 340 * 40 =13600
Now add all these total wages(6100+7500+13600) and divide it by total no of workers i.e 85
MEAN OF MONTHLY WAGES(A) = TOTAL WAGES / NO OF WORKERS TOTAL WAGES (A) = MEAN (A) * NO OF WORKERS(A) TOTAL WAGES (A) = 305 * 20 = 6100 IN THE SAME WAY, TOTAL WAGES (B) = 300* 25 =7500 TOTAL WAGES (C) = 340 * 40 =13600 AND FOR STANDARD DEVIATION : FOR A = √50 SAME B = √40Read more
MEAN OF MONTHLY WAGES(A) = TOTAL WAGES / NO OF WORKERS
Q//Out of 800 families with 4 children each, how many families would be expected to have (1) two boys 2 girls (2) at least one boy (3) no girl (4) at most two girls ? ANSWER: DOWNLOAD ATTACHMENT FOR ANSWER
Q//Out of 800 families with 4 children each, how many families would be expected to have
FOLLOW THE BELOW LINK FOR ANSWER: https://sikshapath.in/question/the-diameter-say-x-of-a-electric-cable-is-assumed-to-be-continuous-random-variable-with-p-d-f/
A computer in a factory is connected to a printer. The printer is located in an office 1 km away …
Answer: serial data transmission reason: serial data transmission more reliable over long distances. less likely for the data to be skewed/out of synchronisation. less interference as only a single wire. a fast connection is not required as a printer is limited by its printing speed
Answer: serial data transmission
reason:
- serial data transmission more reliable over long distances.
- less likely for the data to be skewed/out of synchronisation.
- less interference as only a single wire.
- a fast connection is not required as a printer is limited by its printing speed
See lessThe following data is given for variable values and frequencies x: 0,1,2,3,4,5,6,7,8 and frequencies f: 1,8,28,56,70,56,28,8,1. Find Mu one, …
DOWNLOAD ATTACHMENT FOR ANSWER:
DOWNLOAD ATTACHMENT FOR ANSWER:
See lessA company has three establishments A,B and C in three cities. Analysis of the daily wages paid to the employees …
MEAN OF MONTHLY WAGES(A) = TOTAL WAGES / NO OF WORKERS TOTAL WAGES (A) = MEAN (A) * NO OF WORKERS(A) TOTAL WAGES (A) = 305 * 20 = 6100 IN THE SAME WAY, TOTAL WAGES (B) = 300* 25 =7500 TOTAL WAGES (C) = 340 * 40 =13600 Now add all these total wages(6100+7500+13600) and divide it by totaRead more
MEAN OF MONTHLY WAGES(A) = TOTAL WAGES / NO OF WORKERS
TOTAL WAGES (A) = MEAN (A) * NO OF WORKERS(A)
TOTAL WAGES (A) = 305 * 20 = 6100
IN THE SAME WAY,
TOTAL WAGES (B) = 300* 25 =7500
TOTAL WAGES (C) = 340 * 40 =13600
Now add all these total wages(6100+7500+13600) and divide it by total no of workers i.e 85
AND FOR STANDARD DEVIATION :
FOR A = √50 SAME B = √40 AND C = √ 45
See lessA company has three establishments A,B and C in three cities. Analysis of the daily wages paid to the employees …
MEAN OF MONTHLY WAGES(A) = TOTAL WAGES / NO OF WORKERS TOTAL WAGES (A) = MEAN (A) * NO OF WORKERS(A) TOTAL WAGES (A) = 305 * 20 = 6100 IN THE SAME WAY, TOTAL WAGES (B) = 300* 25 =7500 TOTAL WAGES (C) = 340 * 40 =13600 AND FOR STANDARD DEVIATION : FOR A = √50 SAME B = √40Read more
MEAN OF MONTHLY WAGES(A) = TOTAL WAGES / NO OF WORKERS
TOTAL WAGES (A) = MEAN (A) * NO OF WORKERS(A)
TOTAL WAGES (A) = 305 * 20 = 6100
IN THE SAME WAY,
TOTAL WAGES (B) = 300* 25 =7500
TOTAL WAGES (C) = 340 * 40 =13600
AND FOR STANDARD DEVIATION :
FOR A = √50
SAME B = √40 AND C = √ 45
See lessOut of 800 families with 4 children each, how many families would be expected to have (1) two boys 2 …
Q//Out of 800 families with 4 children each, how many families would be expected to have (1) two boys 2 girls (2) at least one boy (3) no girl (4) at most two girls ? ANSWER: DOWNLOAD ATTACHMENT FOR ANSWER
Q//Out of 800 families with 4 children each, how many families would be expected to have
(1) two boys 2 girls
(2) at least one boy
(3) no girl
(4) at most two girls ?
ANSWER: DOWNLOAD ATTACHMENT FOR ANSWER
See lessThe diameter , Say X , of a electric cable , is assumed to be continuous random variable with p.d.f …
FOLLOW THE BELOW LINK FOR ANSWER: https://sikshapath.in/question/the-diameter-say-x-of-a-electric-cable-is-assumed-to-be-continuous-random-variable-with-p-d-f/
FOLLOW THE BELOW LINK FOR ANSWER:
See less