Consider the following relations:
Salesman
salesman_id | name | city | commission
————-+————+———-+————
5001 | James Hoog | New York | 0.15
5002 | Nail Knite | Paris | 0.13
5005 | Pit Alex | London | 0.11
5006 | Mc Lyon | Paris | 0.14
5007 | Paul Adam | Rome | 0.13
5003 | Lauson Hen | San Jose | 0.12
Customer
customer_id | cust_name | city | grade | salesman_id
————-+—————-+————+——-+————-
3002 | Nick Rimando | New York | 100 | 5001
3007 | Brad Davis | New York | 200 | 5001
3005 | Graham Zusi | California | 200 | 5002
3008 | Julian Green | London | 300 | 5002
3004 | Fabian Johnson | Paris | 300 | 5006
3009 | Geoff Cameron | Berlin | 100 | 5003
3003 | Jozy Altidor | Moscow | 200 | 5007
3001 | Brad Guzan | London | | 5005
Orders
ord_no purch_amt ord_date customer_id salesman_id
———- ———- ———- ———– ———–
70001 150.5 2012-10-05 3005 5002
70009 270.65 2012-09-10 3001 5005
70002 65.26 2012-10-05 3002 5001
70004 110.5 2012-08-17 3009 5003
70007 948.5 2012-09-10 3005 5002
70005 2400.6 2012-07-27 3007 5001
70008 5760 2012-09-10 3002 5001
70010 1983.43 2012-10-10 3004 5006
70003 2480.4 2012-10-10 3009 5003
70012 250.45 2012-06-27 3008 5002
70011 75.29 2012-08-17 3003 5007
70013 3045.6 2012-04-25 3002 5001
Write a query to create a view that shows for each order the salesman and customer by name.
Create table salesman(
salesman_id number (10),
s_name varchar(20),
city varchar(20),
commission number(10,2)
);
insert into salesman values(5001,’James Hoog’,’New York’,0.15);
insert into salesman values(5002,’Nail Knite’,’New York’,0.13);
Checkout Attachment for full answer.